ASVAB Math Knowledge Practice Test 791086 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.59
Score	0%	72%

Review

The endpoints of this line segment are at (-2, -4) and (2, 2). What is the slope-intercept equation for this line?

41% Answer Correctly

	y = -2\(\frac{1}{2}\)x + 0
	y = -2x + 3
	y = 1\(\frac{1}{2}\)x - 1
	y = -\(\frac{1}{2}\)x + 2

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -4) and (2, 2) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(2.0) - (-4.0)}{(2) - (-2)} \) = \( \frac{6}{4} \)
m = 1\(\frac{1}{2}\)

Plugging these values into the slope-intercept equation:

y = 1\(\frac{1}{2}\)x - 1

Solve for z:
z² + 7z + 12 = 0

58% Answer Correctly

	-3 or -4
	1 or -8
	8 or 4
	6 or -3

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

z² + 7z + 12 = 0
(z + 3)(z + 4) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 3) or (z + 4) must equal zero:

If (z + 3) = 0, z must equal -3
If (z + 4) = 0, z must equal -4

So the solution is that z = -3 or -4

If AD = 22 and BD = 17, AB = ?

76% Answer Correctly

	20
	8
	5
	12

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 22 - 17
AB = 5

A quadrilateral is a shape with __________ sides.

91% Answer Correctly

	3
	4
	2
	5

Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

91% Answer Correctly

	addition
	pairs
	division
	exponents

Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)