| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
The dimensions of this cube are height (h) = 2, length (l) = 5, and width (w) = 2. What is the volume?
| 162 | |
| 42 | |
| 20 | |
| 189 |
The volume of a cube is height x length x width:
v = h x l x w
v = 2 x 5 x 2
v = 20
The endpoints of this line segment are at (-2, -10) and (2, 2). What is the slope of this line?
| 2 | |
| \(\frac{1}{2}\) | |
| -3 | |
| 3 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -10) and (2, 2) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(2.0) - (-10.0)}{(2) - (-2)} \) = \( \frac{12}{4} \)Simplify 3a x 8b.
| 24\( \frac{a}{b} \) | |
| 24ab | |
| 24\( \frac{b}{a} \) | |
| 24a2b2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
3a x 8b = (3 x 8) (a x b) = 24ab
Solve 4a + 2a = -2a - 3y + 3 for a in terms of y.
| -\(\frac{3}{10}\)y - \(\frac{7}{10}\) | |
| 8y - 9 | |
| -\(\frac{5}{6}\)y + \(\frac{1}{2}\) | |
| \(\frac{5}{13}\)y + \(\frac{1}{13}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
4a + 2y = -2a - 3y + 3
4a = -2a - 3y + 3 - 2y
4a + 2a = -3y + 3 - 2y
6a = -5y + 3
a = \( \frac{-5y + 3}{6} \)
a = \( \frac{-5y}{6} \) + \( \frac{3}{6} \)
a = -\(\frac{5}{6}\)y + \(\frac{1}{2}\)
If b = 3 and x = 1, what is the value of b(b - x)?
| -275 | |
| -90 | |
| 6 | |
| -20 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
b(b - x)
1(3)(3 - 1)
1(3)(2)
(3)(2)
6