ASVAB Math Knowledge Practice Test 791553 Results

Your Results Global Average
Questions 5 5
Correct 0 2.98
Score 0% 60%

Review

1

Which of the following statements about math operations is incorrect?

71% Answer Correctly

you can subtract monomials that have the same variable and the same exponent

you can multiply monomials that have different variables and different exponents

all of these statements are correct

you can add monomials that have the same variable and the same exponent


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.


2

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

circumference

diameter

chord

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


3

A(n) __________ is to a parallelogram as a square is to a rectangle.

52% Answer Correctly

quadrilateral

triangle

trapezoid

rhombus


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


4

If a = c = 7, b = d = 6, what is the area of this rectangle?

80% Answer Correctly
18
42
28
30

Solution

The area of a rectangle is equal to its length x width:

a = l x w
a = a x b
a = 7 x 6
a = 42


5

Solve for a:
a2 - 59 = -2a + 4

49% Answer Correctly
9 or -3
7 or -9
8 or 4
7 or -7

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

a2 - 59 = -2a + 4
a2 - 59 - 4 = -2a
a2 + + 2a - 63 = 0
a2 + 2a - 63 = 0

Next, factor the quadratic equation:

a2 + 2a - 63 = 0
(a - 7)(a + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (a - 7) or (a + 9) must equal zero:

If (a - 7) = 0, a must equal 7
If (a + 9) = 0, a must equal -9

So the solution is that a = 7 or -9