When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6b + 3b = -3b + 5z - 3 for b in terms of z.
| 1\(\frac{3}{8}\)z + 1 | |
| \(\frac{2}{3}\)z - 1\(\frac{1}{3}\) | |
| z - \(\frac{5}{16}\) | |
| -\(\frac{2}{3}\)z + 1 |