When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 8c = -5c + 6z + 2 for c in terms of z.
| -\(\frac{2}{11}\)z + \(\frac{2}{11}\) | |
| 1\(\frac{6}{11}\)z + \(\frac{7}{11}\) | |
| -1\(\frac{1}{6}\)z + 1\(\frac{1}{6}\) | |
| \(\frac{1}{14}\)z + \(\frac{1}{14}\) |