ASVAB Math Knowledge Practice Test 793510

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6a - 2a = -9a + 4z - 9 for a in terms of z.

\(\frac{2}{5}\)z - \(\frac{1}{2}\)
\(\frac{1}{3}\)z - \(\frac{8}{15}\)
\(\frac{1}{4}\)z + 2\(\frac{1}{4}\)
\(\frac{2}{5}\)z - \(\frac{3}{5}\)