| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.24 |
| Score | 0% | 65% |
The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?
2lw x 2wh + 2lh |
|
h2 x l2 x w2 |
|
lw x wh + lh |
|
h x l x w |
A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.
Solve for b:
5b - 6 > 5 - 9b
| b > 2\(\frac{1}{2}\) | |
| b > -2\(\frac{1}{4}\) | |
| b > -1\(\frac{1}{2}\) | |
| b > \(\frac{11}{14}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
5b - 6 > 5 - 9b
5b > 5 - 9b + 6
5b + 9b > 5 + 6
14b > 11
b > \( \frac{11}{14} \)
b > \(\frac{11}{14}\)
If the area of this square is 16, what is the length of one of the diagonals?
| 5\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 9\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)
Simplify 7a x 5b.
| 12ab | |
| 35ab | |
| 35\( \frac{a}{b} \) | |
| 35a2b2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
7a x 5b = (7 x 5) (a x b) = 35ab
The endpoints of this line segment are at (-2, -7) and (2, 1). What is the slope of this line?
| \(\frac{1}{2}\) | |
| 2\(\frac{1}{2}\) | |
| 2 | |
| 1\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -7) and (2, 1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(1.0) - (-7.0)}{(2) - (-2)} \) = \( \frac{8}{4} \)