| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.94 |
| Score | 0% | 59% |
The endpoints of this line segment are at (-2, 3) and (2, -9). What is the slope of this line?
| -3 | |
| 3 | |
| -\(\frac{1}{2}\) | |
| -2\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 3) and (2, -9) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-9.0) - (3.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)Solve for a:
a2 - 7a - 3 = -a + 4
| -1 or 7 | |
| 9 or 2 | |
| 8 or -6 | |
| 1 or -8 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
a2 - 7a - 3 = -a + 4
a2 - 7a - 3 - 4 = -a
a2 - 7a + a - 7 = 0
a2 - 6a - 7 = 0
Next, factor the quadratic equation:
a2 - 6a - 7 = 0
(a + 1)(a - 7) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (a + 1) or (a - 7) must equal zero:
If (a + 1) = 0, a must equal -1
If (a - 7) = 0, a must equal 7
So the solution is that a = -1 or 7
A quadrilateral is a shape with __________ sides.
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3 |
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4 |
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5 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.
The dimensions of this trapezoid are a = 5, b = 5, c = 6, d = 4, and h = 3. What is the area?
| 22 | |
| 13\(\frac{1}{2}\) | |
| 20 | |
| 11 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(5 + 4)(3)
a = ½(9)(3)
a = ½(27) = \( \frac{27}{2} \)
a = 13\(\frac{1}{2}\)
If the base of this triangle is 3 and the height is 3, what is the area?
| 84 | |
| 15 | |
| 31\(\frac{1}{2}\) | |
| 4\(\frac{1}{2}\) |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 3 x 3 = \( \frac{9}{2} \) = 4\(\frac{1}{2}\)