When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c + 6c = 4c + 4x - 4 for c in terms of x.
| -\(\frac{2}{5}\)x - \(\frac{3}{5}\) | |
| \(\frac{1}{6}\)x + \(\frac{1}{3}\) | |
| \(\frac{1}{4}\)x - \(\frac{5}{12}\) | |
| 2x + 3\(\frac{1}{2}\) |