| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.46 |
| Score | 0% | 49% |
Which types of triangles will always have at least two sides of equal length?
isosceles and right |
|
equilateral, isosceles and right |
|
equilateral and right |
|
equilateral and isosceles |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
What is the circumference of a circle with a diameter of 14?
| 14π | |
| 24π | |
| 12π | |
| 18π |
The formula for circumference is circle diameter x π:
c = πd
c = 14π
Find the value of a:
-a + z = 4
-8a - 4z = -9
| -\(\frac{1}{6}\) | |
| -\(\frac{7}{12}\) | |
| 2\(\frac{1}{4}\) | |
| \(\frac{11}{14}\) |
You need to find the value of a so solve the first equation in terms of z:
-a + z = 4
z = 4 + a
then substitute the result (4 - -1a) into the second equation:
-8a - 4(4 + a) = -9
-8a + (-4 x 4) + (-4 x a) = -9
-8a - 16 - 4a = -9
-8a - 4a = -9 + 16
-12a = 7
a = \( \frac{7}{-12} \)
a = -\(\frac{7}{12}\)
If the length of AB equals the length of BD, point B __________ this line segment.
trisects |
|
bisects |
|
midpoints |
|
intersects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
Solve -3c + 7c = -6c - 4z + 8 for c in terms of z.
| -3\(\frac{2}{3}\)z + 2\(\frac{2}{3}\) | |
| 11z - 8 | |
| -2z + 1 | |
| 1\(\frac{1}{6}\)z + \(\frac{1}{12}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
-3c + 7z = -6c - 4z + 8
-3c = -6c - 4z + 8 - 7z
-3c + 6c = -4z + 8 - 7z
3c = -11z + 8
c = \( \frac{-11z + 8}{3} \)
c = \( \frac{-11z}{3} \) + \( \frac{8}{3} \)
c = -3\(\frac{2}{3}\)z + 2\(\frac{2}{3}\)