When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve c - 2c = -c - 3z + 2 for c in terms of z.
| 3\(\frac{1}{2}\)z + 2\(\frac{1}{2}\) | |
| -\(\frac{1}{5}\)z + 1\(\frac{4}{5}\) | |
| 1\(\frac{1}{3}\)z - 2\(\frac{1}{3}\) | |
| -\(\frac{1}{2}\)z + 1 |