When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 8c = -4c + 2z + 9 for c in terms of z.
| -1\(\frac{2}{5}\)z + \(\frac{4}{5}\) | |
| -15z - 5 | |
| 1\(\frac{2}{7}\)z + \(\frac{5}{7}\) | |
| -\(\frac{6}{7}\)z + 1\(\frac{2}{7}\) |