ASVAB Math Knowledge Practice Test 799892 Results

Your Results Global Average
Questions 5 5
Correct 0 3.20
Score 0% 64%

Review

1

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

87% Answer Correctly

division

addition

pairs

exponents


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


2

Solve for a:
-3a + 5 < 4 - a

54% Answer Correctly
a < \(\frac{2}{3}\)
a < -\(\frac{2}{3}\)
a < \(\frac{1}{2}\)
a < -2

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-3a + 5 < 4 - a
-3a < 4 - a - 5
-3a + a < 4 - 5
-2a < -1
a < \( \frac{-1}{-2} \)
a < \(\frac{1}{2}\)


3

What is 9a + 6a?

80% Answer Correctly
54a
54a2
15a
15

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

9a + 6a = 15a


4

On this circle, line segment CD is the:

46% Answer Correctly

radius

chord

diameter

circumference


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

Solve for b:
b2 - 3b - 61 = -4b - 5

48% Answer Correctly
5 or -6
7 or -8
6 or -6
7 or 5

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

b2 - 3b - 61 = -4b - 5
b2 - 3b - 61 + 5 = -4b
b2 - 3b + 4b - 56 = 0
b2 + b - 56 = 0

Next, factor the quadratic equation:

b2 + b - 56 = 0
(b - 7)(b + 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 7) or (b + 8) must equal zero:

If (b - 7) = 0, b must equal 7
If (b + 8) = 0, b must equal -8

So the solution is that b = 7 or -8