ASVAB Math Knowledge Practice Test 800046 Results

Your Results Global Average
Questions 5 5
Correct 0 2.64
Score 0% 53%

Review

1

The endpoints of this line segment are at (-2, -1) and (2, 1). What is the slope of this line?

46% Answer Correctly
3
\(\frac{1}{2}\)
-3
2

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -1) and (2, 1) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(1.0) - (-1.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)
m = \(\frac{1}{2}\)


2

Simplify (y + 9)(y - 6)

63% Answer Correctly
y2 + 15y + 54
y2 - 15y + 54
y2 - 3y - 54
y2 + 3y - 54

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y + 9)(y - 6)
(y x y) + (y x -6) + (9 x y) + (9 x -6)
y2 - 6y + 9y - 54
y2 + 3y - 54


3

Solve for z:
-3z - 7 = -5 + 5z

59% Answer Correctly
-\(\frac{1}{4}\)
-1\(\frac{1}{3}\)
\(\frac{2}{9}\)
-1\(\frac{3}{5}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-3z - 7 = -5 + 5z
-3z = -5 + 5z + 7
-3z - 5z = -5 + 7
-8z = 2
z = \( \frac{2}{-8} \)
z = -\(\frac{1}{4}\)


4

Solve for a:
-a + 4 < \( \frac{a}{8} \)

44% Answer Correctly
a < -3
a < -2\(\frac{2}{3}\)
a < 3\(\frac{5}{9}\)
a < -\(\frac{2}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-a + 4 < \( \frac{a}{8} \)
8 x (-a + 4) < a
(8 x -a) + (8 x 4) < a
-8a + 32 < a
-8a + 32 - a < 0
-8a - a < -32
-9a < -32
a < \( \frac{-32}{-9} \)
a < 3\(\frac{5}{9}\)


5

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

4π r2

2(π r2) + 2π rh

π r2h2

π r2h


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.