ASVAB Math Knowledge Practice Test 801329 Results

Your Results Global Average
Questions 5 5
Correct 0 2.40
Score 0% 48%

Review

1

If a = c = 7, b = d = 8, and the blue angle = 80°, what is the area of this parallelogram?

65% Answer Correctly
56
9
36
30

Solution

The area of a parallelogram is equal to its length x width:

a = l x w
a = a x b
a = 7 x 8
a = 56


2

The formula for the area of a circle is which of the following?

24% Answer Correctly

c = π r2

c = π r

c = π d

c = π d2


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


3

Which of the following statements about math operations is incorrect?

70% Answer Correctly

you can subtract monomials that have the same variable and the same exponent

you can multiply monomials that have different variables and different exponents

you can add monomials that have the same variable and the same exponent

all of these statements are correct


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.


4

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

diameter

circumference

chord

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

Solve 6b - b = 3b + 2x - 2 for b in terms of x.

34% Answer Correctly
7\(\frac{1}{2}\)x - 3
3\(\frac{3}{4}\)x - 2
x - \(\frac{2}{3}\)
6x + 6

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

6b - x = 3b + 2x - 2
6b = 3b + 2x - 2 + x
6b - 3b = 2x - 2 + x
3b = 3x - 2
b = \( \frac{3x - 2}{3} \)
b = \( \frac{3x}{3} \) + \( \frac{-2}{3} \)
b = x - \(\frac{2}{3}\)