The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

z² - 12z + 35 = 0
(z - 5)(z - 7) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 5) or (z - 7) must equal zero:

If (z - 5) = 0, z must equal 5
If (z - 7) = 0, z must equal 7

So the solution is that z = 5 or 7

You need to find the value of a so solve the first equation in terms of y:

-a + y = -1
y = -1 + a

then substitute the result (-1 - -1a) into the second equation:

-7a + 9(-1 + a) = -9
-7a + (9 x -1) + (9 x a) = -9
-7a - 9 + 9a = -9
-7a + 9a = -9 + 9
2a = 0
a = \( \frac{0}{2} \)
a =

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

The formula for area is πr². Radius is circle \( \frac{diameter}{2} \):

r = \( \frac{d}{2} \)
r = \( \frac{8}{2} \)
r = 4
a = πr²
a = π(4²)
a = 16π

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

8a⁴ + 5a⁴ = 13a⁴