When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 4c = -2c - 5z - 6 for c in terms of z.
| -1\(\frac{1}{8}\)z - \(\frac{3}{4}\) | |
| 12z - 9 | |
| z - \(\frac{1}{6}\) | |
| -\(\frac{2}{15}\)z - \(\frac{1}{15}\) |