ASVAB Math Knowledge Practice Test 802288

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve b + 2b = 9b + 4z - 2 for b in terms of z.

-\(\frac{1}{4}\)z + \(\frac{1}{4}\)
-3z + 2
-\(\frac{2}{11}\)z - \(\frac{3}{11}\)
-\(\frac{12}{13}\)z - \(\frac{2}{13}\)