ASVAB Math Knowledge Practice Test 802569 Results

Your Results Global Average
Questions 5 5
Correct 0 2.28
Score 0% 46%

Review

1

Which of the following statements about a parallelogram is not true?

49% Answer Correctly

the area of a parallelogram is base x height

opposite sides and adjacent angles are equal

a parallelogram is a quadrilateral

the perimeter of a parallelogram is the sum of the lengths of all sides


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


2

Solve -4a - a = a - 7x - 4 for a in terms of x.

34% Answer Correctly
-\(\frac{1}{2}\)x + 1
1\(\frac{1}{5}\)x + \(\frac{4}{5}\)
-\(\frac{7}{13}\)x - \(\frac{3}{13}\)
-2x + \(\frac{1}{2}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

-4a - x = a - 7x - 4
-4a = a - 7x - 4 + x
-4a - a = -7x - 4 + x
-5a = -6x - 4
a = \( \frac{-6x - 4}{-5} \)
a = \( \frac{-6x}{-5} \) + \( \frac{-4}{-5} \)
a = 1\(\frac{1}{5}\)x + \(\frac{4}{5}\)


3

A(n) __________ is to a parallelogram as a square is to a rectangle.

51% Answer Correctly

quadrilateral

rhombus

triangle

trapezoid


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


4

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

midpoints

intersects

trisects

bisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


5

The dimensions of this cylinder are height (h) = 5 and radius (r) = 8. What is the surface area?

48% Answer Correctly
96π
210π
208π
16π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(82) + 2π(8 x 5)
sa = 2π(64) + 2π(40)
sa = (2 x 64)π + (2 x 40)π
sa = 128π + 80π
sa = 208π