| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.30 |
| Score | 0% | 66% |
The dimensions of this cube are height (h) = 8, length (l) = 3, and width (w) = 3. What is the volume?
| 120 | |
| 144 | |
| 72 | |
| 210 |
The volume of a cube is height x length x width:
v = h x l x w
v = 8 x 3 x 3
v = 72
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
division |
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exponents |
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pairs |
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addition |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
If side a = 9, side b = 1, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{40} \) | |
| \( \sqrt{82} \) | |
| \( \sqrt{52} \) | |
| \( \sqrt{73} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 92 + 12
c2 = 81 + 1
c2 = 82
c = \( \sqrt{82} \)
Which of the following statements about a parallelogram is not true?
the area of a parallelogram is base x height |
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the perimeter of a parallelogram is the sum of the lengths of all sides |
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a parallelogram is a quadrilateral |
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opposite sides and adjacent angles are equal |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
Solve for a:
-4a + 4 > \( \frac{a}{-1} \)
| a > 2\(\frac{1}{2}\) | |
| a > 1\(\frac{1}{3}\) | |
| a > -2\(\frac{1}{3}\) | |
| a > \(\frac{9}{40}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-4a + 4 > \( \frac{a}{-1} \)
-1 x (-4a + 4) > a
(-1 x -4a) + (-1 x 4) > a
4a - 4 > a
4a - 4 - a > 0
4a - a > 4
3a > 4
a > \( \frac{4}{3} \)
a > 1\(\frac{1}{3}\)