| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.70 |
| Score | 0% | 54% |
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
obtuse, acute |
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supplementary, vertical |
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acute, obtuse |
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vertical, supplementary |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
A trapezoid is a quadrilateral with one set of __________ sides.
right angle |
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parallel |
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equal angle |
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equal length |
A trapezoid is a quadrilateral with one set of parallel sides.
The endpoints of this line segment are at (-2, -3) and (2, 7). What is the slope of this line?
| 1\(\frac{1}{2}\) | |
| -2 | |
| -1 | |
| 2\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -3) and (2, 7) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(7.0) - (-3.0)}{(2) - (-2)} \) = \( \frac{10}{4} \)Solve for c:
4c + 7 > 4 - 5c
| c > 1\(\frac{1}{2}\) | |
| c > -2\(\frac{1}{2}\) | |
| c > 3\(\frac{1}{2}\) | |
| c > -\(\frac{1}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
4c + 7 > 4 - 5c
4c > 4 - 5c - 7
4c + 5c > 4 - 7
9c > -3
c > \( \frac{-3}{9} \)
c > -\(\frac{1}{3}\)
Find the value of a:
-2a + z = 4
6a + 6z = 3
| 25 | |
| 1 | |
| -1\(\frac{1}{6}\) | |
| -9 |
You need to find the value of a so solve the first equation in terms of z:
-2a + z = 4
z = 4 + 2a
then substitute the result (4 - -2a) into the second equation:
6a + 6(4 + 2a) = 3
6a + (6 x 4) + (6 x 2a) = 3
6a + 24 + 12a = 3
6a + 12a = 3 - 24
18a = -21
a = \( \frac{-21}{18} \)
a = -1\(\frac{1}{6}\)