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Solve for b:
-9b + 8 < -8 + 6b
| b < \(\frac{1}{2}\) | |
| b < 1\(\frac{1}{15}\) | |
| b < -1\(\frac{1}{7}\) | |
| b < \(\frac{5}{8}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-9b + 8 < -8 + 6b
-9b < -8 + 6b - 8
-9b - 6b < -8 - 8
-15b < -16
b < \( \frac{-16}{-15} \)
b < 1\(\frac{1}{15}\)
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
supplementary, vertical |
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vertical, supplementary |
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obtuse, acute |
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acute, obtuse |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
Which of the following statements about a parallelogram is not true?
the area of a parallelogram is base x height |
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opposite sides and adjacent angles are equal |
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a parallelogram is a quadrilateral |
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the perimeter of a parallelogram is the sum of the lengths of all sides |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
Simplify (3a)(3ab) - (9a2)(8b).
| 102ab2 | |
| 81ab2 | |
| -63a2b | |
| 102a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(3a)(3ab) - (9a2)(8b)
(3 x 3)(a x a x b) - (9 x 8)(a2 x b)
(9)(a1+1 x b) - (72)(a2b)
9a2b - 72a2b
-63a2b
Solve for a:
a2 + 3a - 35 = 3a + 1
| -4 or -7 | |
| 6 or 5 | |
| 6 or -6 | |
| -1 or -4 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
a2 + 3a - 35 = 3a + 1
a2 + 3a - 35 - 1 = 3a
a2 + 3a - 3a - 36 = 0
a2 - 36 = 0
Next, factor the quadratic equation:
a2 - 36 = 0
(a - 6)(a + 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (a - 6) or (a + 6) must equal zero:
If (a - 6) = 0, a must equal 6
If (a + 6) = 0, a must equal -6
So the solution is that a = 6 or -6