ASVAB Math Knowledge Practice Test 804955 Results

Your Results Global Average
Questions 5 5
Correct 0 2.71
Score 0% 54%

Review

1

Solve for b:
-9b + 8 < -8 + 6b

54% Answer Correctly
b < \(\frac{1}{2}\)
b < 1\(\frac{1}{15}\)
b < -1\(\frac{1}{7}\)
b < \(\frac{5}{8}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-9b + 8 < -8 + 6b
-9b < -8 + 6b - 8
-9b - 6b < -8 - 8
-15b < -16
b < \( \frac{-16}{-15} \)
b < 1\(\frac{1}{15}\)


2

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

supplementary, vertical

vertical, supplementary

obtuse, acute

acute, obtuse


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


3

Which of the following statements about a parallelogram is not true?

49% Answer Correctly

the area of a parallelogram is base x height

opposite sides and adjacent angles are equal

a parallelogram is a quadrilateral

the perimeter of a parallelogram is the sum of the lengths of all sides


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


4

Simplify (3a)(3ab) - (9a2)(8b).

59% Answer Correctly
102ab2
81ab2
-63a2b
102a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(3a)(3ab) - (9a2)(8b)
(3 x 3)(a x a x b) - (9 x 8)(a2 x b)
(9)(a1+1 x b) - (72)(a2b)
9a2b - 72a2b
-63a2b


5

Solve for a:
a2 + 3a - 35 = 3a + 1

48% Answer Correctly
-4 or -7
6 or 5
6 or -6
-1 or -4

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

a2 + 3a - 35 = 3a + 1
a2 + 3a - 35 - 1 = 3a
a2 + 3a - 3a - 36 = 0
a2 - 36 = 0

Next, factor the quadratic equation:

a2 - 36 = 0
(a - 6)(a + 6) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (a - 6) or (a + 6) must equal zero:

If (a - 6) = 0, a must equal 6
If (a + 6) = 0, a must equal -6

So the solution is that a = 6 or -6