ASVAB Math Knowledge Practice Test 805062

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6c + 2c = -6c - 6y - 3 for c in terms of y.

-\(\frac{2}{3}\)y - \(\frac{1}{4}\)
\(\frac{1}{3}\)y - \(\frac{1}{4}\)
\(\frac{1}{12}\)y - \(\frac{3}{4}\)
y - \(\frac{3}{4}\)