When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 2c = -4c + 5z + 4 for c in terms of z.
| \(\frac{1}{4}\)z + \(\frac{1}{3}\) | |
| \(\frac{4}{11}\)z + \(\frac{6}{11}\) | |
| -2\(\frac{1}{4}\)z - \(\frac{3}{4}\) | |
| 3z + 1\(\frac{4}{5}\) |