| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.84 |
| Score | 0% | 57% |
If angle a = 47° and angle b = 28° what is the length of angle d?
| 133° | |
| 123° | |
| 135° | |
| 147° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 47° - 28° = 105°
So, d° = 28° + 105° = 133°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 47° = 133°
Simplify (4a)(7ab) - (9a2)(2b).
| -10ab2 | |
| 10a2b | |
| 121ab2 | |
| 121a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(4a)(7ab) - (9a2)(2b)
(4 x 7)(a x a x b) - (9 x 2)(a2 x b)
(28)(a1+1 x b) - (18)(a2b)
28a2b - 18a2b
10a2b
If a = c = 5, b = d = 3, and the blue angle = 75°, what is the area of this parallelogram?
| 15 | |
| 1 | |
| 28 | |
| 21 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 5 x 3
a = 15
The dimensions of this trapezoid are a = 4, b = 3, c = 5, d = 3, and h = 3. What is the area?
| 9 | |
| 18 | |
| 19\(\frac{1}{2}\) | |
| 17\(\frac{1}{2}\) |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(3 + 3)(3)
a = ½(6)(3)
a = ½(18) = \( \frac{18}{2} \)
a = 9
Solve for c:
2c - 1 > -9 - c
| c > -2\(\frac{2}{3}\) | |
| c > -3\(\frac{1}{2}\) | |
| c > -\(\frac{7}{8}\) | |
| c > -2 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
2c - 1 > -9 - c
2c > -9 - c + 1
2c + c > -9 + 1
3c > -8
c > \( \frac{-8}{3} \)
c > -2\(\frac{2}{3}\)