ASVAB Math Knowledge Practice Test 809686

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2c - 8c = 7c + 4z - 5 for c in terms of z.

\(\frac{6}{17}\)z - \(\frac{9}{17}\)
-2\(\frac{2}{5}\)z + 1
-3\(\frac{1}{5}\)z + \(\frac{4}{5}\)
1\(\frac{4}{5}\)z + 1\(\frac{3}{5}\)