When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 3c = 5c - 2z + 6 for c in terms of z.
| \(\frac{8}{9}\)z - \(\frac{2}{9}\) | |
| -10z - 2 | |
| 2\(\frac{1}{2}\)z - 3 | |
| -7z - 9 |