When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve c - 2c = -4c + 8z + 4 for c in terms of z.
| -1\(\frac{2}{5}\)z + 1\(\frac{4}{5}\) | |
| \(\frac{3}{5}\)z - \(\frac{3}{5}\) | |
| \(\frac{1}{13}\)z - \(\frac{4}{13}\) | |
| 2z + \(\frac{4}{5}\) |