| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.15 |
| Score | 0% | 43% |
The formula for the area of a circle is which of the following?
c = π r2 |
|
c = π d2 |
|
c = π r |
|
c = π d |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
The dimensions of this cylinder are height (h) = 4 and radius (r) = 1. What is the surface area?
| 60π | |
| 240π | |
| 108π | |
| 10π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(12) + 2π(1 x 4)
sa = 2π(1) + 2π(4)
sa = (2 x 1)π + (2 x 4)π
sa = 2π + 8π
sa = 10π
Solve for b:
4b - 2 > 8 + 8b
| b > -1 | |
| b > -2\(\frac{1}{2}\) | |
| b > \(\frac{1}{8}\) | |
| b > 1\(\frac{1}{4}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
4b - 2 > 8 + 8b
4b > 8 + 8b + 2
4b - 8b > 8 + 2
-4b > 10
b > \( \frac{10}{-4} \)
b > -2\(\frac{1}{2}\)
If angle a = 69° and angle b = 24° what is the length of angle d?
| 133° | |
| 116° | |
| 111° | |
| 148° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 69° - 24° = 87°
So, d° = 24° + 87° = 111°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 69° = 111°
Solve -5b + b = 9b - 7y + 3 for b in terms of y.
| -1\(\frac{3}{7}\)y + \(\frac{4}{7}\) | |
| y + \(\frac{9}{17}\) | |
| \(\frac{4}{7}\)y - \(\frac{3}{14}\) | |
| 2\(\frac{1}{2}\)y + 2 |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-5b + y = 9b - 7y + 3
-5b = 9b - 7y + 3 - y
-5b - 9b = -7y + 3 - y
-14b = -8y + 3
b = \( \frac{-8y + 3}{-14} \)
b = \( \frac{-8y}{-14} \) + \( \frac{3}{-14} \)
b = \(\frac{4}{7}\)y - \(\frac{3}{14}\)