When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2c + 2c = -3c + 3z + 1 for c in terms of z.
| 1\(\frac{1}{10}\)z + \(\frac{3}{5}\) | |
| -z + 3 | |
| z + 1 | |
| -1\(\frac{1}{3}\)z - 2\(\frac{1}{3}\) |