| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.36 |
| Score | 0% | 67% |
Which of the following is not true about both rectangles and squares?
the lengths of all sides are equal |
|
the perimeter is the sum of the lengths of all four sides |
|
all interior angles are right angles |
|
the area is length x width |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
Which of the following statements about math operations is incorrect?
you can multiply monomials that have different variables and different exponents |
|
you can add monomials that have the same variable and the same exponent |
|
you can subtract monomials that have the same variable and the same exponent |
|
all of these statements are correct |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
A right angle measures:
45° |
|
90° |
|
180° |
|
360° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.
Solve for b:
-b + 8 = -9 + 2b
| \(\frac{1}{7}\) | |
| 5\(\frac{2}{3}\) | |
| \(\frac{5}{8}\) | |
| -\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-b + 8 = -9 + 2b
-b = -9 + 2b - 8
-b - 2b = -9 - 8
-3b = -17
b = \( \frac{-17}{-3} \)
b = 5\(\frac{2}{3}\)
Factor y2 + 12y + 36
| (y + 6)(y - 6) | |
| (y + 6)(y + 6) | |
| (y - 6)(y - 6) | |
| (y - 6)(y + 6) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 36 as well and sum (Inside, Outside) to equal 12. For this problem, those two numbers are 6 and 6. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 12y + 36
y2 + (6 + 6)y + (6 x 6)
(y + 6)(y + 6)