| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.25 |
| Score | 0% | 65% |
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
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π r2h2 |
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2(π r2) + 2π rh |
|
4π r2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Solve for a:
a - 6 < -1 - 3a
| a < 1\(\frac{1}{4}\) | |
| a < -1\(\frac{1}{2}\) | |
| a < -\(\frac{5}{9}\) | |
| a < -\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
a - 6 < -1 - 3a
a < -1 - 3a + 6
a + 3a < -1 + 6
4a < 5
a < \( \frac{5}{4} \)
a < 1\(\frac{1}{4}\)
The dimensions of this cylinder are height (h) = 5 and radius (r) = 4. What is the volume?
| 80π | |
| 147π | |
| 16π | |
| 243π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(42 x 5)
v = 80π
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
exponents |
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addition |
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division |
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pairs |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve for z:
z2 + 14z + 48 = 0
| 6 or -7 | |
| 8 or -8 | |
| -6 or -8 | |
| 5 or -6 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 + 14z + 48 = 0
(z + 6)(z + 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 6) or (z + 8) must equal zero:
If (z + 6) = 0, z must equal -6
If (z + 8) = 0, z must equal -8
So the solution is that z = -6 or -8