ASVAB Math Knowledge Practice Test 813719

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6c - 7c = -6c + y + 2 for c in terms of y.

\(\frac{2}{3}\)y + \(\frac{1}{6}\)
-5\(\frac{2}{3}\)y - \(\frac{1}{3}\)
\(\frac{1}{5}\)y + \(\frac{4}{5}\)
4y - 1