ASVAB Math Knowledge Practice Test 81566

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -b + 6b = -4b + 6x - 4 for b in terms of x.

x - \(\frac{5}{6}\)
1\(\frac{1}{3}\)x + 2\(\frac{1}{3}\)
x - 1\(\frac{1}{3}\)
\(\frac{5}{8}\)x + \(\frac{1}{4}\)