When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -a - 5a = -5a - 6z - 1 for a in terms of z.
| \(\frac{2}{5}\)z + \(\frac{9}{10}\) | |
| \(\frac{1}{5}\)z - 1\(\frac{2}{5}\) | |
| \(\frac{2}{15}\)z - \(\frac{8}{15}\) | |
| -\(\frac{1}{4}\)z - \(\frac{1}{4}\) |