ASVAB Math Knowledge Practice Test 817755 Results

Your Results Global Average
Questions 5 5
Correct 0 3.00
Score 0% 60%

Review

1

A(n) __________ is two expressions separated by an equal sign.

77% Answer Correctly

expression

formula

equation

problem


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


2

If BD = 19 and AD = 21, AB = ?

76% Answer Correctly
15
1
2
11

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 21 - 19
AB = 2


3

The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?

68% Answer Correctly

lw x wh + lh

h2 x l2 x w2

h x l x w

2lw x 2wh + 2lh


Solution

A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.


4

Solve -2a + 3a = 3a - 4z - 1 for a in terms of z.

34% Answer Correctly
z + \(\frac{3}{8}\)
1\(\frac{2}{5}\)z + \(\frac{1}{5}\)
-\(\frac{2}{7}\)z - 1\(\frac{2}{7}\)
7z - 9

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

-2a + 3z = 3a - 4z - 1
-2a = 3a - 4z - 1 - 3z
-2a - 3a = -4z - 1 - 3z
-5a = -7z - 1
a = \( \frac{-7z - 1}{-5} \)
a = \( \frac{-7z}{-5} \) + \( \frac{-1}{-5} \)
a = 1\(\frac{2}{5}\)z + \(\frac{1}{5}\)


5

Find the value of b:
7b + y = 5
-9b - 5y = 4

42% Answer Correctly
1\(\frac{1}{5}\)
16
1\(\frac{3}{26}\)
-\(\frac{23}{26}\)

Solution

You need to find the value of b so solve the first equation in terms of y:

7b + y = 5
y = 5 - 7b

then substitute the result (5 - 7b) into the second equation:

-9b - 5(5 - 7b) = 4
-9b + (-5 x 5) + (-5 x -7b) = 4
-9b - 25 + 35b = 4
-9b + 35b = 4 + 25
26b = 29
b = \( \frac{29}{26} \)
b = 1\(\frac{3}{26}\)