ASVAB Math Knowledge Practice Test 8198

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5c + 6c = -c + 3x - 9 for c in terms of x.

-\(\frac{2}{3}\)x - 2
-\(\frac{1}{2}\)x - 1\(\frac{1}{2}\)
-\(\frac{1}{3}\)x + \(\frac{5}{12}\)
\(\frac{1}{2}\)x + \(\frac{1}{2}\)