ASVAB Math Knowledge Practice Test 82079

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5b - 4b = 2b - 7z + 6 for b in terms of z.

3\(\frac{2}{5}\)z - \(\frac{3}{5}\)
-\(\frac{3}{7}\)z + \(\frac{1}{2}\)
-z + 2
-2z + 1\(\frac{4}{5}\)