| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
Solve for b:
5b + 8 = \( \frac{b}{2} \)
| 2 | |
| 1\(\frac{13}{22}\) | |
| -\(\frac{35}{39}\) | |
| -1\(\frac{7}{9}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
5b + 8 = \( \frac{b}{2} \)
2 x (5b + 8) = b
(2 x 5b) + (2 x 8) = b
10b + 16 = b
10b + 16 - b = 0
10b - b = -16
9b = -16
b = \( \frac{-16}{9} \)
b = -1\(\frac{7}{9}\)
Which of the following statements about math operations is incorrect?
you can add monomials that have the same variable and the same exponent |
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you can subtract monomials that have the same variable and the same exponent |
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you can multiply monomials that have different variables and different exponents |
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all of these statements are correct |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
If a = c = 4, b = d = 5, and the blue angle = 66°, what is the area of this parallelogram?
| 10 | |
| 7 | |
| 2 | |
| 20 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 4 x 5
a = 20
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
division |
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exponents |
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addition |
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pairs |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve for z:
6z - 6 > \( \frac{z}{4} \)
| z > -1\(\frac{17}{37}\) | |
| z > 1\(\frac{1}{23}\) | |
| z > -2\(\frac{7}{19}\) | |
| z > -\(\frac{21}{25}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
6z - 6 > \( \frac{z}{4} \)
4 x (6z - 6) > z
(4 x 6z) + (4 x -6) > z
24z - 24 > z
24z - 24 - z > 0
24z - z > 24
23z > 24
z > \( \frac{24}{23} \)
z > 1\(\frac{1}{23}\)