ASVAB Math Knowledge Practice Test 820859 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

Solve for z:
-4z + 5 = 4 - 9z

59% Answer Correctly
-\(\frac{1}{5}\)
6
\(\frac{4}{5}\)
-1\(\frac{3}{5}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-4z + 5 = 4 - 9z
-4z = 4 - 9z - 5
-4z + 9z = 4 - 5
5z = -1
z = \( \frac{-1}{5} \)
z = -\(\frac{1}{5}\)


2

The dimensions of this cube are height (h) = 4, length (l) = 7, and width (w) = 2. What is the volume?

83% Answer Correctly
56
84
36
24

Solution

The volume of a cube is height x length x width:

v = h x l x w
v = 4 x 7 x 2
v = 56


3

Solve for c:
c2 - 15c + 56 = 0

58% Answer Correctly
3 or -8
7 or -4
7 or 8
9 or 6

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

c2 - 15c + 56 = 0
(c - 7)(c - 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 7) or (c - 8) must equal zero:

If (c - 7) = 0, c must equal 7
If (c - 8) = 0, c must equal 8

So the solution is that c = 7 or 8


4

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the perimeter is the sum of the lengths of all four sides

all interior angles are right angles

the area is length x width

the lengths of all sides are equal


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


5

What is the area of a circle with a radius of 4?

70% Answer Correctly
16π
81π
36π

Solution

The formula for area is πr2:

a = πr2
a = π(42)
a = 16π