ASVAB Math Knowledge Practice Test 821105

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6a + 3a = -4a - 6z - 9 for a in terms of z.

4\(\frac{1}{2}\)z + 4\(\frac{1}{2}\)
-z + \(\frac{1}{2}\)
-\(\frac{3}{5}\)z - \(\frac{3}{5}\)
\(\frac{1}{7}\)z + \(\frac{6}{7}\)