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Simplify 6a x 7b.
13ab | |
42ab | |
42\( \frac{a}{b} \) | |
42a2b2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
6a x 7b = (6 x 7) (a x b) = 42ab
If the area of this square is 4, what is the length of one of the diagonals?
8\( \sqrt{2} \) | |
9\( \sqrt{2} \) | |
4\( \sqrt{2} \) | |
2\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
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2(π r2) + 2π rh |
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π r2h2 |
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4π r2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Solve for z:
-7z - 7 > \( \frac{z}{-1} \)
z > -1\(\frac{1}{6}\) | |
z > 2\(\frac{2}{5}\) | |
z > -1\(\frac{8}{19}\) | |
z > \(\frac{9}{10}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-7z - 7 > \( \frac{z}{-1} \)
-1 x (-7z - 7) > z
(-1 x -7z) + (-1 x -7) > z
7z + 7 > z
7z + 7 - z > 0
7z - z > -7
6z > -7
z > \( \frac{-7}{6} \)
z > -1\(\frac{1}{6}\)
Which of the following expressions contains exactly two terms?
quadratic |
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polynomial |
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monomial |
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binomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.