| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.06 |
| Score | 0% | 61% |
If a = 9, b = 2, c = 8, and d = 4, what is the perimeter of this quadrilateral?
| 23 | |
| 18 | |
| 19 | |
| 22 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 9 + 2 + 8 + 4
p = 23
Which of the following is not true about both rectangles and squares?
the area is length x width |
|
the lengths of all sides are equal |
|
the perimeter is the sum of the lengths of all four sides |
|
all interior angles are right angles |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
Find the value of c:
4c + z = 2
-7c - 5z = 3
| \(\frac{11}{14}\) | |
| \(\frac{5}{32}\) | |
| -\(\frac{1}{8}\) | |
| 1 |
You need to find the value of c so solve the first equation in terms of z:
4c + z = 2
z = 2 - 4c
then substitute the result (2 - 4c) into the second equation:
-7c - 5(2 - 4c) = 3
-7c + (-5 x 2) + (-5 x -4c) = 3
-7c - 10 + 20c = 3
-7c + 20c = 3 + 10
13c = 13
c = \( \frac{13}{13} \)
c = 1
The dimensions of this cube are height (h) = 4, length (l) = 1, and width (w) = 6. What is the surface area?
| 246 | |
| 68 | |
| 280 | |
| 270 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 1 x 6) + (2 x 6 x 4) + (2 x 1 x 4)
sa = (12) + (48) + (8)
sa = 68
Simplify (4a)(9ab) - (9a2)(4b).
| 2b | |
| 0a2b | |
| 72a2b | |
| 169a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(4a)(9ab) - (9a2)(4b)
(4 x 9)(a x a x b) - (9 x 4)(a2 x b)
(36)(a1+1 x b) - (36)(a2b)
36a2b - 36a2b
0a2b