When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c - 3c = -9c - 5x + 3 for c in terms of x.
| 1\(\frac{2}{5}\)x + \(\frac{1}{5}\) | |
| -6x - 5 | |
| -2x + 3 | |
| \(\frac{1}{6}\)x - \(\frac{2}{3}\) |