The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -3. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -5) and (2, -1) so the slope becomes:

Plugging these values into the slope-intercept equation:

y = x - 3

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

a² + 14a + 49 = 0
(a + 7)(a + 7) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, (a + 7) must equal zero:

If (a + 7) = 0, a must equal -7

So the solution is that a = -7

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

a² - 14a + 34 = -2a - 2
a² - 14a + 34 + 2 = -2a
a² - 14a + 2a + 36 = 0
a² - 12a + 36 = 0

Next, factor the quadratic equation:

a² - 12a + 36 = 0
(a - 6)(a - 6) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, (a - 6) must equal zero:

If (a - 6) = 0, a must equal 6

So the solution is that a = 6

You need to find the value of b so solve the first equation in terms of x:

6b + x = -4
x = -4 - 6b

then substitute the result (-4 - 6b) into the second equation:

-6b + 1(-4 - 6b) = -6
-6b + (1 x -4) + (1 x -6b) = -6
-6b - 4 - 6b = -6
-6b - 6b = -6 + 4
-12b = -2
b = \( \frac{-2}{-12} \)
b = \(\frac{1}{6}\)

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 5 + 2 + 1 + 6
p = 14