When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 5c = 6c + 2x - 2 for c in terms of x.
| 8x - 2 | |
| -2\(\frac{1}{3}\)x + \(\frac{2}{3}\) | |
| \(\frac{3}{5}\)x + \(\frac{4}{15}\) | |
| 3x + 4 |