When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 4c = -c + 5x - 6 for c in terms of x.
| -2\(\frac{3}{4}\)x + 1\(\frac{3}{4}\) | |
| \(\frac{2}{15}\)x + \(\frac{7}{15}\) | |
| -3x - 3 | |
| 1\(\frac{4}{5}\)x - 1\(\frac{1}{5}\) |