ASVAB Math Knowledge Practice Test 829451 Results

Your Results Global Average
Questions 5 5
Correct 0 3.25
Score 0% 65%

Review

1

A coordinate grid is composed of which of the following?

88% Answer Correctly

all of these

y-axis

x-axis

origin


Solution

The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.


2

Which of the following statements about a parallelogram is not true?

49% Answer Correctly

a parallelogram is a quadrilateral

the perimeter of a parallelogram is the sum of the lengths of all sides

the area of a parallelogram is base x height

opposite sides and adjacent angles are equal


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


3

What is the circumference of a circle with a radius of 10?

71% Answer Correctly
20π
16π

Solution

The formula for circumference is circle diameter x π. Circle diameter is 2 x radius:

c = πd
c = π(2 * r)
c = π(2 * 10)
c = 20π


4

If c = 1 and x = 5, what is the value of 7c(c - x)?

68% Answer Correctly
-672
-28
-64
324

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

7c(c - x)
7(1)(1 - 5)
7(1)(-4)
(7)(-4)
-28


5

Solve for z:
-6z + 1 = \( \frac{z}{-2} \)

46% Answer Correctly
-1\(\frac{17}{47}\)
6\(\frac{6}{7}\)
-2
\(\frac{2}{11}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-6z + 1 = \( \frac{z}{-2} \)
-2 x (-6z + 1) = z
(-2 x -6z) + (-2 x 1) = z
12z - 2 = z
12z - 2 - z = 0
12z - z = 2
11z = 2
z = \( \frac{2}{11} \)
z = \(\frac{2}{11}\)