| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.56 |
| Score | 0% | 51% |
This diagram represents two parallel lines with a transversal. If w° = 13, what is the value of d°?
| 15 | |
| 163 | |
| 167 | |
| 160 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with w° = 13, the value of d° is 167.
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h2 |
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4π r2 |
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2(π r2) + 2π rh |
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π r2h |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Which of the following statements about parallel lines with a transversal is not correct?
all acute angles equal each other |
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angles in the same position on different parallel lines are called corresponding angles |
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all of the angles formed by a transversal are called interior angles |
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same-side interior angles are complementary and equal each other |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
If the length of AB equals the length of BD, point B __________ this line segment.
midpoints |
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intersects |
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bisects |
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trisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
Solve for c:
6c - 9 = \( \frac{c}{-1} \)
| \(\frac{3}{4}\) | |
| \(\frac{63}{64}\) | |
| -1\(\frac{5}{13}\) | |
| 1\(\frac{2}{7}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
6c - 9 = \( \frac{c}{-1} \)
-1 x (6c - 9) = c
(-1 x 6c) + (-1 x -9) = c
-6c + 9 = c
-6c + 9 - c = 0
-6c - c = -9
-7c = -9
c = \( \frac{-9}{-7} \)
c = 1\(\frac{2}{7}\)