| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.89 |
| Score | 0% | 58% |
Which types of triangles will always have at least two sides of equal length?
equilateral and isosceles |
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equilateral, isosceles and right |
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isosceles and right |
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equilateral and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
Solve for z:
z2 + 4z + 3 = 0
| -1 or -3 | |
| 4 or -5 | |
| 5 or -8 | |
| 6 or -9 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 + 4z + 3 = 0
(z + 1)(z + 3) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 1) or (z + 3) must equal zero:
If (z + 1) = 0, z must equal -1
If (z + 3) = 0, z must equal -3
So the solution is that z = -1 or -3
Factor y2 - 11y + 24
| (y - 8)(y + 3) | |
| (y + 8)(y - 3) | |
| (y - 8)(y - 3) | |
| (y + 8)(y + 3) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 24 as well and sum (Inside, Outside) to equal -11. For this problem, those two numbers are -8 and -3. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 11y + 24
y2 + (-8 - 3)y + (-8 x -3)
(y - 8)(y - 3)
For this diagram, the Pythagorean theorem states that b2 = ?
c2 - a2 |
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c2 + a2 |
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c - a |
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a2 - c2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
If AD = 23 and BD = 21, AB = ?
| 2 | |
| 6 | |
| 14 | |
| 11 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD